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A 5.0 A A g) What is the current through the second resistor? omega resistor? V

ID: 1373828 • Letter: A

Question

A 5.0 A A g) What is the current through the second resistor? omega resistor? V f) What is the current through the 5.0 V e) What is the voltage drop across the second resistor omega resistor? V d)What is the voltage drop across the 5.0 omega b) What is the current out of the battery? A c) What is the voltage out of the battery? omega b) What is the equivalent resistance across the combination of the two resistors? omega resistor and a second resistor are connected in series across a 25.0 V battery. A current of 4.0 A flows through the first resistor. Analyze the circuit to determine the values described below. Hint, use the grid method to solve for unknowns and then fill then in values below. (They will not necessarily be in order.) a) What is the resistance of the second resistor?

Explanation / Answer

a) V= IR

since R= R1+R2 where R1 = 5

therefore

25= 4*(5+R2)

R2=1.25 ohms

b)R1+R2 = 6.25 ohms

c) the current out of battery is 4A

d) vltage out of battery is 25V

e) voltage drop across 2nd register V =I*R = 4*1.25 = 5V

f)the current through 5ohm resister is 4A

g)the current through second resistor is 4A

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