A concave spherical mirror has a radius of curvature of 16.0 cm. Locate the imag
ID: 1375167 • Letter: A
Question
A concave spherical mirror has a radius of curvature of 16.0 cm. Locate the image for each of the following object distances. (Enter 0 for M and the distance if no image is formed.)
(a) do = 32.0 cm
M = ______ ,
di = ____ cm, and
what Orientation ?--- (in front of the mirror, real, and upright) OR (in front of the mirror, real, and inverted) OR (behind the mirror, virtual, and upright) OR (behind the mirror, virtual, and inverted) OR (no image is formed)
(b) do = 16.0 cm
M = ______ ,
di = _______ cm, and ---
What Orientation?--- (in front of the mirror, real, and upright) OR (in front of the mirror, real, and inverted) OR (behind the mirror, virtual, and upright) OR (behind the mirror, virtual, and inverted) OR (no image is formed)
(c) do = 8.0 cm
M =_______ ,
di =________ cm, and ---
What Orientation?--- (in front of the mirror, real, and upright) OR (in front of the mirror, real, and inverted) OR (behind the mirror, virtual, and upright) OR (behind the mirror, virtual, and inverted) OR (no image is formed)
Explanation / Answer
As R = 16.0 cm, then f = R/2 = 8.0 cm.
Note that
1/f = 1/do + 1/di
where
f = focal length = 8 cm
do = object distance = 32 cm
di = image distance
Thus, solving for di,
di = 10.66666667 cm
Thus, the magnification, m = -di/do,
m = -0.333333333
**********************************
Note that
1/f = 1/do + 1/di
where
f = focal length = 8 cm
do = object distance = 16 cm
di = image distance
Thus, solving for di,
di = 16 cm
Thus, the magnification, m = -di/do,
m = -1
**********************************
Note that
1/f = 1/do + 1/di
where
f = focal length = 8 cm
do = object distance = 8 cm
di = image distance
Thus, solving for di,
di = infinity cm [no image]
Thus, the magnification, m = -di/do,
m = 0
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