A spring with a spring constant of 38N/cm has a cage attached to one end. How mu

Question

A spring with a spring constant of 38N/cm has a cage attached to one end. How much work does the spring force do on the cage if the spring is stretched from its relaxed length by 7.6 mm?

How much additional work is done by the spring force if it is stretched by an additional 7.6 mm?

A spring with a spring constant of 38N/cm has a cage attached to one end. How much work does the spring force do on the cage if the spring is stretched from its relaxed length by 7.6 mm? How much additional work is done by the spring force if it is stretched by an additional 7.6 mm?

Explanation / Answer

W = .5Kx^2

    = .5*38*(.0076)^2

   = 1.097 *10^-3 J

Additional Work = .5K(x2^2 - x1^2)

= .5*38*(.0152^2 - .0076^2 )

    = 3.292*10^-3 J

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.