The kinetic energy of a rolling billiard ball is given by KE=1/2 m v 2. Suppose

Question

The kinetic energy of a rolling billiard ball is given by KE=1/2mv2. Suppose a 0.17-kg billiard ball is rolling down a pool table with an initial speed of 4.5m/s . As it travels, it loses some of its energy as heat. The ball slows down to 3.7m/s and then collides straight-on with a second billiard ball of equal mass. The first billiard ball completely stops and the second one rolls away with a velocity of 3.7m/s . Assume the first billiard ball is the system

Calculate q for the process.

Express your answer using one significant figure.

Explanation / Answer

The lost KE is converted to Q (heat), thus,

Q = |1/2 m (vf^2 - vi^2)|

Thus,

Q = 0.5576 J

or

Q = 0.6 J [ANSWER]

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