Light of wavelength 640nm from a distant source is incident on a slit 0.770mm wi

Question

Light of wavelength 640nm from a distant source is incident on a slit 0.770mm wide, and the resulting diffraction pattern is observed on a screen 3.10m away.

Part A

What is the distance between the two dark fringes on either side of the central bright fringe?

6.440

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Light of wavelength 640nm from a distant source is incident on a slit 0.770mm wide, and the resulting diffraction pattern is observed on a screen 3.10m away.

Part A

What is the distance between the two dark fringes on either side of the central bright fringe?

6.440

SubmitMy AnswersGive Up

Incorrect; Try Again; 5 attempts remaining

Explanation / Answer

Distance between the two dark fringes on either side of the central bright fringe 2*y = 2*lamda*D/d

lamda is the wavelength of the light = 640*10^-9 m

width of the slit is 0.77*10^-3 m

Distnce of the screen from the slits is D = 3.1 m

then required distamce is 2*y = (2*640*10^-9*3.1)/(0.77*10^-3)

2y = 5.15*10^-3 m = 5.15 mm

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