Light of wavelength 632.8nm is incident normally on a system of 4 narrow slits.

Question

Light of wavelength 632.8nm is incident normally on a system of 4 narrow slits. Each slit is 0.04 mm wide, and the centre of each slit is 0.12mm from the centre of the adjacent slit. An intensity pattern is observed on a distant screen.

a) Three of the slits are blocked, so that light shines through only one slit. Taking the direction from the slit system to the centre of the fringe pattern to be 0deg, what is the angle to the first point of zero intensity?

b) A second slit, adjacent to the first, is now uncovered. How many visible interference fringes are there within the central diffraction maximum?

c) Now, all four slits are uncovered. What is the angle to the first point of zero intensity in the resulting pattern?

Explanation / Answer

a) 0.906 degrees

b) d/a = .12/.04 = 3

c) 0.0755 degrees

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