A square coil is made up of 16.00 loops that are 2.70 cm long. The coil is place

Question

A square coil is made up of 16.00 loops that are 2.70 cm long. The coil is placed in a uniform 320.0 mT magnetic field and subjected to a  current of 60.0 mA.

a) What torque in N-m will be exerted on the coil when the magnetic field is parallel to the plane of the coil?

b) What torque in N-m will be exerted on the coil when the magnetic field is perpendicular to the plane of the coil?

c) What torque in N-m will be exerted on the coil when the magnetic field makes an angle of 44.0 with the plane of the loop?

Explanation / Answer

Here ,

Magnetic moment , M = 16 * 0.027^2 * 0.060

M = 6.998 *10^-4 A.m^2

torque is given as M X B = MB * sin(theta)

a)

Now, for parallel to the plane

Torque =   6.998 *10^-4 * 0.320 * sin(90)

Torque = 2.24 *10^-4 N.m

b)

for perpendicular

theta = 0

hence ,

Torque = 0

c)

theta = 90 - 44

theta = 46 degree

Torque =   6.998 *10^-4 * 0.320 * sin(46)

Torque = 1.61 *10^-4 N.m

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