At t = 0s, the leading edge of a wave (wavelength 1m) is 3m to the left of a bou

Question

At t = 0s, the leading edge of a wave (wavelength 1m) is 3m to the left of a boundary. The wave is moving to the right at 1m/s. The transmitted wave has wavelength 3m. (You may draw pictures to help you answer the questions below, but you must explicitly state - in words - the answers to the questions.)

(a)[8 pt(s) ]At t = 5s, where is the leading edge of the transmitted wave? Is the transmitted wave inverted or non-inverted, and why?

(b)[7 pt(s) ]At t = 5s, where is the leading edge of the reflected wave? Is the reflected wave inverted or non-inverted, and why?

(c)[4 pt(s) ]How does the period of a complete wave compare on each side of the boundary?

Explanation / Answer

assuming the wave is transmitted in less dense medium
transmitted wave is at at 2 m beyond boundry non invertd wave because the more dense medium was originally at rest, an upward pull can do nothing but cause an upward displacement
reflected wave is at 2 m inside boundry, inverted wave because more dense medium overpowers the smaller mass of the last particle of the less dense medium. This causes an upward displaced pulse to become a downward displaced pulse

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.