In an effort to stay awake for an all-night study session, a student makes a cup
ID: 1387071 • Letter: I
Question
In an effort to stay awake for an all-night study session, a student makes a cup of coffee by first placing a 204W electric immersion heater in 0.335kg of water. Part A How much heat must be added to the water to raise its temperature from 21.0?C to 78.4?C? Q = J Part B How much time is required if all of the heater's power goes into heating the water? t = sIn an effort to stay awake for an all-night study session, a student makes a cup of coffee by first placing a 204W electric immersion heater in 0.335kg of water. Part A How much heat must be added to the water to raise its temperature from 21.0?C to 78.4?C? Q = J Part B How much time is required if all of the heater's power goes into heating the water? t = s
In an effort to stay awake for an all-night study session, a student makes a cup of coffee by first placing a 204W electric immersion heater in 0.335kg of water. In an effort to stay awake for an all-night study session, a student makes a cup of coffee by first placing a 204W electric immersion heater in 0.335kg of water. In an effort to stay awake for an all-night study session, a student makes a cup of coffee by first placing a 204W electric immersion heater in 0.335kg of water. Part A How much heat must be added to the water to raise its temperature from 21.0?C to 78.4?C? Q = J Part B How much time is required if all of the heater's power goes into heating the water? t = s
Part A How much heat must be added to the water to raise its temperature from 21.0?C to 78.4?C? Q = J Part A How much heat must be added to the water to raise its temperature from 21.0?C to 78.4?C? Q = J Q = J Q = J Part B How much time is required if all of the heater's power goes into heating the water? t = s
Part B How much time is required if all of the heater's power goes into heating the water? t = s
t = s
t = s
Q = J
Explanation / Answer
A)
Swater , specific heat of water = 4.186 J/gm.C
Now ,
heat used, Q = m*Swater*change in temperature
Q = 335 * 4.186 *(78.4 - 21)
Q = 80492 J
heat added to water is 80492 J
B)
as energy = power * time
80492 = 204 * t
t = 394.6 s
the time taken is 394.6 s
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