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In an effort to stay awake for an all-night study session, a student makes a cup

ID: 1387071 • Letter: I

Question

In an effort to stay awake for an all-night study session, a student makes a cup of coffee by first placing a 204W electric immersion heater in 0.335kg of water. Part A How much heat must be added to the water to raise its temperature from 21.0?C to 78.4?C? Q =   J   SubmitGive Up Part B How much time is required if all of the heater's power goes into heating the water? t =   s  
In an effort to stay awake for an all-night study session, a student makes a cup of coffee by first placing a 204W electric immersion heater in 0.335kg of water. Part A How much heat must be added to the water to raise its temperature from 21.0?C to 78.4?C? Q =   J   SubmitGive Up Part B How much time is required if all of the heater's power goes into heating the water? t =   s  
In an effort to stay awake for an all-night study session, a student makes a cup of coffee by first placing a 204W electric immersion heater in 0.335kg of water. In an effort to stay awake for an all-night study session, a student makes a cup of coffee by first placing a 204W electric immersion heater in 0.335kg of water. In an effort to stay awake for an all-night study session, a student makes a cup of coffee by first placing a 204W electric immersion heater in 0.335kg of water. Part A How much heat must be added to the water to raise its temperature from 21.0?C to 78.4?C? Q =   J   SubmitGive Up Part B How much time is required if all of the heater's power goes into heating the water? t =   s  
Part A How much heat must be added to the water to raise its temperature from 21.0?C to 78.4?C? Q =   J   SubmitGive Up Part A How much heat must be added to the water to raise its temperature from 21.0?C to 78.4?C? Q =   J   SubmitGive Up Q =   J   Q =   J   SubmitGive Up Part B How much time is required if all of the heater's power goes into heating the water? t =   s  
Part B How much time is required if all of the heater's power goes into heating the water? t =   s  
t =   s  
t =   s  
Q =   J  

Explanation / Answer

A)

Swater , specific heat of water = 4.186 J/gm.C

Now ,

heat used, Q = m*Swater*change in temperature

Q = 335 * 4.186 *(78.4 - 21)

Q = 80492 J

heat added to water is 80492 J

B)

as energy = power * time

80492 = 204 * t

t = 394.6 s

the time taken is 394.6 s

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