An air puck of mass m1 = 0.18 kg is tied to a string and allowed to revolve in a

Question

An air puck of mass m1 = 0.18 kg is tied to a string and allowed to revolve in a circle of radius R = 0.9 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of m2 = 0.8 kg is tied to it (see the figure below). The suspended mass remains in equilibrium while the puck on the tabletop revolves. (a) What is the tension in the string? Incorrect: Your answer is incorrect. Your response differs from the correct answer by more than 10%. Double check your calculations. N (b) What is the horizontal force acting on the puck? N (c) What is the speed of the puck? m/s

Explanation / Answer

here ,

a)

for the frictionless table ,

Tension in the string , T = m2 *g

T = 0.8 * 9.8

T = 7.84 N

the tension in the string is 7.84 N

b)

horizontal force = T

Horizontal force = 7.84 N

the horizontal force acting on the puck is 7.84 N

c)

as T = m1v^2/R

7.84 = 0.18 * v^2/.9

v = 6.26 m/s

the speed of puck is 6.26 m/s

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