An RL circuit in which L=2.00H and R=5.00 is connected to a 12.0V battery at t=0

Q: An RL circuit in which L=2.00H and R=5.00 is connected to a 12.0V battery at t=0

a) energy is stored in the inductor, U = 0.5*L*I^2 = 0.5*2*1.76^2 = 3.1 J b) Power going to the inductor = power delivered by the baattery - power disssipated at resistor = V*I - I^2*R = 12*1.76 - 1.76^2*5 = 5.63 Watts

ID: 1399945 • Letter: A

Question

An RL circuit in which L=2.00H and R=5.00 is connected to a 12.0V battery at t=0.

(a)

What energy is stored in the inductor when I= 1.76 A ?Previous Submissions:

Try 1: Correct. Your answer: "3.61 J". The data used on this submission: 1.9 A;

J ( ± 0.01 J)

(b)

What is the power going into the inductor at the same current?Previous Submissions:

Try 1: Incorrect. Your answer: "3.6 W". Correct answer: "6.6 W". The data used on this submission: 0.85 A;

W ( ± 0.1 W)

I don't get why the power isn't calculated by P=i^2R

Explanation / Answer

a) energy is stored in the inductor, U = 0.5*L*I^2

= 0.5*2*1.76^2

= 3.1 J

b) Power going to the inductor = power delivered by the baattery - power disssipated at resistor

= V*I - I^2*R

= 12*1.76 - 1.76^2*5

= 5.63 Watts

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An RL circuit in which L=2.00H and R=5.00 is connected to a 12.0V battery at t=0

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Explanation / Answer

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