A charged particle with a charge to mass ratio of 5.7E8 C/kg travels on a circul

Question

A charged particle with a charge to mass ratio of 5.7E8 C/kg travels on a circular path that is perpendicular to a magnetic field whose magnitude is 0.27 T. How much time does it take for the particle to complete one revolution? A charged particle with a charge to mass ratio of 5.7E8 C/kg travels on a circular path that is perpendicular to a magnetic field whose magnitude is 0.27 T. How much time does it take for the particle to complete one revolution? A charged particle with a charge to mass ratio of 5.7E8 C/kg travels on a circular path that is perpendicular to a magnetic field whose magnitude is 0.27 T. How much time does it take for the particle to complete one revolution?

Explanation / Answer

Here ,

for the particle , q/m = 5.78 *10^8 C/kg

magnetic field , B = 0.27 T

time taken to complete one revolution = 2pi*m/(B*q)

time taken to complete one revolution = 2pi*(1/(0.27 * 5.78 *10^5))

time taken to complete one revolution = 4.03 *10^-5 s

the time taken to complete one revolution is 4.03 *10^-5 s

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