Two 10-cm diameter charged rings face each other, 10cm apart. The left ring is c

Question

Two 10-cm diameter charged rings face each other, 10cm apart. The left ring is charged to -25nC and the right ring is charged to +25nC.

Part A:) What is the magnitude of the electric field at the midpoint of the two rings?
E= Value & Units


Part B:) What is the direction of the electric field at the midpoint of the two rings?
A. To the left ring.

B. To the right ring.

C. Parallel to the plane of the rings.

Part C:) What is the magnitude of the force on a -1.0nC charge placed at the midpoint?

F= Value & Units

Part D:) What is the direction of the force on a -1.0 nC charged placed at the midpoint?
A. To the right ring.

B. Parallel to the plane of the rings.

C. To the left ring.

Explanation / Answer

Here ,

radius of ring , r = 10/2 = 5 cm

r = 0.05 m

distance of midpoint , d = 10/2 = 5 cm

d = 0.05 m

Now , as the electric field at the midpoint due to bioth the rings wil be in same direction and the equal in magnitude ,

Enet = 2 * k * Q*d/sqrt(d^2 + r^2)^3

Enet = 2 * 9*10^9 * 25 *10^-9 * 0.05/sqrt((0.05^2 + 0.05^2)^3)

Enet = 6.36 *10^4 N/C

the net electric field at the midpoint is 6.36 *10^4 N/C

part B)
as the elertric field is towards the negative ring ,

A> to the left ring

part C)

magnitude of force = q * E

magnitude of force = 1 *10^-9 * 6.36 *10^4

magnitude of force = 6.36 *10^-5 N

the magnitude of force acting on the charge is 6.36 *10^-5 N

part D)

as the charge is negative ,

the direction of force on the charge is A) to the right

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