Two 10- c m -diameter charged rings face each other, 25 c m apart. The left ring

Question

Two 10-cm-diameter charged rings face each other, 25cm apart. The left ring is charged to -23nC and the right ring is charged to +23nC .

1- What is the magnitude of the electric field E? at the midpoint between the two rings?

2- What is the direction of the electric field E? at the midpoint between the two rings?

3- What is the magnitude of the force F? on a -1.0 nC charge placed at the midpoint?

4- What is the direction of the force F? on a -1.0 nC charge placed at the midpoint?

Please show with steps

Explanation / Answer

E for a single ring
E= k Qb/ (a^2 + b^2) ^3/2
For the given problem
E = 2 k Qb/ (a^2 + b^2) ^3/2

b = 12.5 * 10^-2

a = 5 * 10^-2

1)

E = 2*9*10^9*23*10^-9*12.5*10^-2 / (10^-4 *(5^2 + 12.5^2))^(3/2)

E = 21207.688 N/C

2)

away from the +23 charge

3)

Force = E*q

F = 21207.688*1*10^-9

F = 21.21 * 10^-6 N

4)

towards the +23nC charge ring

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