A lab runs a cross of a wild type silk moth and a tester moth and produces 800 o
ID: 140680 • Letter: A
Question
A lab runs a cross of a wild type silk moth and a tester moth and produces 800 offspring as a result. Given the information in the table below, what is the recombination frequency of the cross?
Phenotype
Expected
Observed
Black eyes
solid wings
210
347
Black eyes banded wings
190
46
Red eyes
solid wings
185
34
Red eyes
banded wings
205
373
Total
800
800
a.
0.1
b.
800
c.
80
d.
0.8
Phenotype
Expected
Observed
Black eyes
solid wings
210
347
Black eyes banded wings
190
46
Red eyes
solid wings
185
34
Red eyes
banded wings
205
373
Total
800
800
Explanation / Answer
Recombinant frequency = Black eyes banded wings + Red eyes solid wings / Total
Because in observed value which trait is shows lowest number undergoes recombination.
Recombinant frequency = 46 + 34 / 100
= 80 / 800
= 0.1
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