An electron traveling at 5 × 10 6 m / s enters a 0 . 1 m region with a uniform e

Question

An electron traveling at 5 × 10 6 m / s enters a 0 . 1 m region with a uniform electric field of 136 N / C , as in the figure.

(A) Please explain all,Find the magnitude of the acceleration of the electron while in the electric field. The mass of an electron is 9 . 109 × 10 ? 31 kg and the fundamental charge is 1 . 602 × 10 ? 19 C .

____________Answer in units of m / s 2

(B)Please Explain all, Find the time it takes the electron to travel through the region of the electric field, assum- ing it doesn’t hit the side walls.

____________Answer in units of s.

(C) Please Explain all, What is the magnitude of the vertical dis- placement ? y of the electron while it is in the electric field?

_______________Answer in units of m

Explanation / Answer

1. apply the condition of equillibrium as gravitational force = electrical force

mg = Eq

where

E is electric filed

q is charge

g is accleration due to gravity

m is mass of the electron

so

a = Eq/m

a = 136*1.6 e -19/(9.11 e-31)

a = 2.38 *10^13 m/s^2

-----------------------------------------

apply the Kinematic equation V = u + at

t = V/a

t = 5e 6/(2.38 e 13)

t = 210 ns

----------------------------------------

apply again H = ut - 0.5 gt^2

H = 2.38 e 13 * 210 e-9 * 210 e-9/2

H = 52.4 cm

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