An electron moving perpendicular to a magnetic field of 3.2 times 10^-2 T moves

Question

An electron moving perpendicular to a magnetic field of 3.2 times 10^-2 T moves in a circle at radius 0.40 cm. How fast is this electron moving (m_e - 9.11 times 10^-31 kg)? A wire of a certain length is carrying a current of 20 A. It is placed at an angle of 60 degree with respect to a magnetic field of strength 020 if the wire experiences a force of 0.40 N, what is the length of the wire? A 4-ohm resistor is connected in parallel with a 12-ohm resistor and this combination is connected to a DC power supply with voltage V as shown in Figure 21-3. If the total current in this circuit is 2 A, what is the value of voltage V?

Explanation / Answer

10) qvB = mv^2 / r

v = qBr / m

= 1.6*10^-19 * 3.2*10^-2 * 0.004 / 9.11*!0^-31

= 2.25*10^7 m/s

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