Calculate the magnitude of the electric field at one corner of a square 2.42 m o

Question

Calculate the magnitude of the electric field at one corner of a square 2.42 m on a side if the other three comers are occupied by 5.25 times 10^_6 C charge. Part B What is the direction of the electric field at the corner? along the side of the square between the corner and one of the charges outward of the charge along the line between the comer and the center of the square outward of the center along the side of the square between the corner and one of the charges toward the charge along the line between the corner and the center of the square toward the center

Explanation / Answer

Part A)    Horizontal electric field = 8.98 * 109 * 5.25 * 10-6 * (1/2.422 + cos45/3.4222)

                                                      =   10897 N/C

              Vertical electric field =    8.98 * 109 * 5.25 * 10-6 * (1/2.422 + sin45/3.4222)

                                                 =   10897 N/C

   => magnitude of electric field = 15410.685 N/C

Part B)   Direction = along the line between the corner and the centre of the square outward of the centre .

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