5. velocity of an objectsubjected to a constant force Record the graph of the ve

Question

5. velocity of an objectsubjected to a constant force Record the graph of the velocities for each of the motions (A, B, and C) from above. Does this velocity versus time graph exhibit a straight-line? If so, is it a straight line having a positive slope, a negative 10 slope, or a zero slope? Does the velocity change in value? If so, how does it change? Time (s) 10 Does this velocity versus time graph exhibit a straight-line? If so, is it a straight line having a positive slope, a negative slope, or a zero slope? Does the velocity change in value? If 5.20 so, how does it change? Time (s) Does this velocity versus time graph exhibit a straight-line? If so, is it a straight line having a positive slope, a negative slope, or a zero slope? Does the velocity change in value? so, how does it change? 10 Time (s)

Explanation / Answer

A) Does this velocity versus time graphs exhibit a straight-line? if so, is it a straight-line having a positive slope, negative slope or zero slope? Does the velocity change in value? if so, how does it change.    Yes. It has a positive slope because the value of the velocity is increasing. The velocity change its value in the form V(t)=m*t+b where m is the slope of the curve. We don't have exact point's value in this curve for that reason it isn't possible obtain that change. If we had points on the curve, we can obtain the slope with the position of two points on the curve follows:     m=(V1-Vo)/(t1-to) where V1 and t1 are the velocity and time of the point 1 and V0 and t0 are the velocity and time of the point 0.  

B) Does this velocity versus time graphs exhibit a straight-line? if so, is it a straight-line having a positive slope, negative slope or zero slope? Does the velocity change in value? if so, how does it change.

    If we considere this plot we have two straight-line with different slope, i.e there was an acceleration or deceleration depends on whether the slope is positive or negative, respectively. Here, both of them have negative slope because the velocity is decreasing and the change of velocity is given by V(t)=m*t+b where slope is given by m=(V1-Vo)/(t1-to).

C) Does this velocity versus time graphs exhibit a straight-line? if so, is it a straight-line having a positive slope, negative slope or zero slope? Does the velocity change in value? if so, how does it change.

   Yes. It has a negative slope because the value of the velocity is decreasing. The velocity change its value in the form V(t)=m*t+b where m is the slope of the curve. We don't have exact point's value in this curve for that reason it isn't possible obtain that change. If we had points on the curve, we can obtain the slope with the position of two points on the curve follows: m=(V1-Vo)/(t1-to) where V1 and t1 are the velocity and time of the point 1 and V0 and t0 are the velocity and time of the point 0.  

Note: in the three images can not be distinguished exact positions of the points of the curve therefore has not achieved the change in the speed value but explained how to get it.

   

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