Two horizontal forces, F^rightarrow_1 and F^rightarrow_2. are acting on a box, b

Question

Two horizontal forces, F^rightarrow_1 and F^rightarrow_2. are acting on a box, but only F^rightarrow_a is shown in the driving. F^rightarrow_2 can Point either to the right or to the left. The box moves only along the x axis. There is no friction between the box and the surface Suppose that F^rightarrow_1 = +2.2 N and the mass of the box is 3.5 kg. Find the magnitude and direction of F^rightarrow_2 when the acceleration of the box is the following. Find the magnitude and direction of F^rightarrow_2 when the acceleration of the box is = 5.5 m/s^2. (Indicate the direction of the force by the sign of your answer.) F^rightarrow_2 =. Find the magnitude and direction of F^rightarrow_2 when the acceleration of the box is 5.5 m/s^2. (Indicate the direction of the force by the sign of your answer.) F^rightarrow_2 =. Find the magnitude and direction of F^rightarrow_2 when the acceleration of the box is 0 m/s^2. (Indicate the direction of the force by the sign of your answer.) F^rightarrow_2 =

Explanation / Answer

F1 = +2.2 N

m = 3.5 kg

a = +5.5 m/sec^2

Newton's law:

F = m*a

total force F = F1 + F2 = m*a

2.2 + F2 = 3.5*5.5

F2 = 3.5*5.5 - 2.2 = 17.05 N in +x direction

magnitude = 17.05 N

B.

2.2 + F2 = 3.5*(-5.5)

F2 = -3.5*5.5 - 2.2 = -21.45 N

magnitude = 21.45N

direction = -ve x

C.

2.2 + F2 = 3.5*0

F2 = -2.2 N

magnitude = 2.2 N

direction = -ve x

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