Two horizontal forces, 1 and 2, are acting on a box, but only 1 is shown in the

Question

Two horizontal forces, 1 and 2, are acting on a box, but only 1 is shown in the drawing. 2 can point either to the right or to the left. The box moves only along the x axis. There is no friction between the box and the surface. Suppose that 1 = +3.0 N and the mass of the box is 3.1 kg. Find the magnitude and direction of 2 when the acceleration of the box is the following.

(a) Find the magnitude and direction of 2 when the acceleration of the box is +6.3 m/s2. (Indicate the direction of the force by the sign of your answers.)

(b) Find the magnitude and direction of 2 when the acceleration of the box is -6.3 m/s2. (Indicate the direction of the force by the sign of your answers.)

(c) Find the magnitude and direction of 2 when the acceleration of the box is 0 m /s2. (Indicate the direction of the force by the sign of your answers.)

Explanation / Answer

a) a = Fnet/m = (F1 + F2)/m so F2 = m*a - F1 = 3.1kg*6.3m/s^2 -3 =16.53N b) so F2 = m*a - F1 = 3.1kg*(-6.3m/s^2) - 2.8 = -22.5N c) so F2 = m*a - F1 = 3.1kg*0m/s^2 - 3 = -3N

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