You and a friend are playing tennis. Earth is the object of reference. Part A Wh

Question

You and a friend are playing tennis. Earth is the object of reference.

Part A

What is the magnitude of the momentum of the 0.057-kg tennis ball when it travels at a speed of 36m/s?

Part B

At what speed must your 0.32-kg tennis racket move to have the same magnitude momentum as the ball?

Part C

If you run toward the ball at a speed of 4.0 m/s, and the ball is flying directly at you at a speed of 36m/s, what is the magnitude of the total momentum of the system (you and the ball)? Assume your mass is 60 kg.

You and a friend are playing tennis. Earth is the object of reference.

Part A

What is the magnitude of the momentum of the 0.057-kg tennis ball when it travels at a speed of 36m/s?

Part B

At what speed must your 0.32-kg tennis racket move to have the same magnitude momentum as the ball?

Part C

If you run toward the ball at a speed of 4.0 m/s, and the ball is flying directly at you at a speed of 36m/s, what is the magnitude of the total momentum of the system (you and the ball)? Assume your mass is 60 kg.

Explanation / Answer

Given m = 0.057kg , v = 36m/s

A) what is the magnitude of the momentum ?

we know momentum = m*v

= 0.057*38 = 2.166kg-m/s

b) speed ?

again momentum = mv

now this case m = 0.32kg , momentum = 2.166kg-m/s

v = momentum/mass = 2.166kg-m/s / 0.32kg = 6.76 m/s

c) what is magntitude of the total momentum of the system

assume mass m = 60kg , v =4.0m/s ,Velocity of ball = 36m/s, mass of ball 0.057kg ,

momentum p = m1v1 + m2v2

p = (60kg * 4.0m/s) + (0.057kg *36m/s) = 242 kgm/s

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