You and a friend are riding bikes one afternoon. You start 3 minutes ahead of he

Question

You and a friend are riding bikes one afternoon. You start 3 minutes
ahead of her from her carport, pedaling 5m/s for 10 minutes when you spot your kid brother playing with a lizard
by the road. After you had stopped for 5 minutes to chat, your friend passes by, oblivious to both you and the
fact that she has forgotten her sack lunch at her house. Since you don’t want to be left behind but your friend
needs her lunch, you immediately pedal back towards her house twice as fast as when you left. When you are
halfway to the house, your speedy friend catches up, having ?nally remembered her lunch. Consider away from
her house to be the positive direction, and that time starts for her entire trip when she leaves.
(a)[5 pt(s) ]What was her average velocity for the entire trip?

Explanation / Answer

average velocity = total displacement / time taken total displacement is from her house to the halfway now total displacement is (5*10*60)/2 m. = 1500 m total time taken is 10+5+(1500)/(10*60) = 17.5 minutes avg velocity = 1500/(17.5*60) = 1.43 m/s

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