A wheel with moment of inertia 1.27 kgm^2 is rotating wit an angular speed of 82

Question

A wheel with moment of inertia 1.27 kgm^2 is rotating wit an angular speed of 824 rev/min on a shaft whose moment of inertia is negligible. A second wheel, initially at rest and with moment of inertia 4.85 kgm^2 is suddenly coupled to the same shaft.
What is the final angular velocity of the resultant combination of the shaft and the two wheels ?
Show all steps please A wheel with moment of inertia 1.27 kgm^2 is rotating wit an angular speed of 824 rev/min on a shaft whose moment of inertia is negligible. A second wheel, initially at rest and with moment of inertia 4.85 kgm^2 is suddenly coupled to the same shaft.
What is the final angular velocity of the resultant combination of the shaft and the two wheels ?
Show all steps please A wheel with moment of inertia 1.27 kgm^2 is rotating wit an angular speed of 824 rev/min on a shaft whose moment of inertia is negligible. A second wheel, initially at rest and with moment of inertia 4.85 kgm^2 is suddenly coupled to the same shaft.
What is the final angular velocity of the resultant combination of the shaft and the two wheels ?
Show all steps please

Explanation / Answer

Final angular velocity = (1.27 * 824)/(1.27 + 4.85)

                                   = 171 rev/min

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