There is a compressed spring between two laboratory carts of masses m_1 = 165 g

Question

There is a compressed spring between two laboratory carts of masses m_1 = 165 g and m_2 = 272 g. Initially, the carts are held at rest on a horizontal track as shown in figure A. The carts are released, and the cart of mass m_1 has velocity v_1 = 1.735i m/s in the positive x direction as in figure B. Assume rolling friction is negligible. (a) What is the net external force on the two-cart system? (Express your answer in vector form.) F = N (b) Find the velocity of cart 2. (Express your answer in vector form.) v_2 = m/s

Explanation / Answer

A.

Net external force on the two cart system is zero .

Because spring force is internal force whose resultant will be zero

B.

Since net force for the system is zero

Hence final momentum=initial momentum = 0

m1v1+m2 v2 =0

So

v2 = - 1.05 i m/s

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