An electron beam moves toward an oscilloscope screen. An electron is accelerated

Question

An electron beam moves toward an oscilloscope screen. An electron is accelerated from rest between cathode and anode through a potential difference of 10000 V along x axis and travels toward the screen which is placed at a distance 0.50 m away from the anode. Assume Earth's magnetic field is perpendicular to the x axis and has the magnitude of 4.0 × 105 T. z axis is perpendicular to the x axis and the Earth's magnetic field.

Part A

How much will the magnetic field deflect the electron's position at the screen? Neglect the changes of the x component of the velocity of the electron and the z component of the acceleration of the electron when it moves from the anode to the screen.

Explanation / Answer

Here, radius of curvature = (m/eB) * sqrt(2eV/m)

                                          = (9.11 *10-31/1.6 *10-19* 4.0 × 105) * sqrt(2 *1.6 *10-19*10000/9.11 *10-31)

                                            =   1.423 * 10-7    * 59.26 *106 m

                                             =   8.432 m

also,    8.432 = (0.25 + x2)/ 2x

=> x = 0.0148 m      -----------------------> magnetic field deflect the electron's position at the screen

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.