When a force is applied to an object with mass equal to the standard kilogram, t

Question

When a force is applied to an object with mass equal to the standard kilogram, the acceleration of the mass is 3.25 m/s^2. (Assume that friction is so small that it can be ignored) When the same magnitude force is applied to another object, the acceleration is 2.75 m/s^2. What is the mass of this object? What would the second object's acceleration be if a force twice as large were applied to if Show your calculations. Given an object with mass equal to the standard kilogram, how would you determine if a force applied to it has magnitude equal to one newton? (Assume that frictional forces are so small that they can be ignored.)

Explanation / Answer

3. F1= m1*a1 = 1.0*3.25 = 3.25 N

By the condition,

F2= F1= 3.25N

F2= m2*a2

3.25 = m2*2.75    => m2=1.18 kg

When F2= 2F1= 2*3.25 = 6.5 N

F2= m2*a2

3.25 = m2*2.75    => m2=1.18 kg

F2= m2*a2

6.5 = 1.18*a2    => a2=5.5m/s^2

4. Use Newton’s second law,

F= m*a

Calculate acceleration using kinematic equation,

a= (vf-vi)/t

Plug values of m and a in above equation and calculate F.

Since m=1.0kg , a must = 1.0m/s^2 to get F=1.0N

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