Calculate the x-and y- components of the electrical field produced at point p (a

Question

Calculate the x-and y- components of the electrical field produced at point p (at the center of the square) by the four chargers placed at the corners of the squares. The length of each side of the square is .4m . The charges have the following values: q1= 1.5 * 10^-6 C, q2= -8.2 * 10^-6 C, q3= -3.9 * 10^-6C, and q4= -8 * 10^-6 C. Be sure to indicate wether each component, If nonzero, is positive or negative for the coordinate system. Thanks, please show all work
Hether each component, if non Whether each component, if non nate system. 42 0.40 m T4 0.40 m

Explanation / Answer

r = 0.5*sqrt(0.4^2+0.4^2) = 0.28 m

E1x = k*q1*cos45/r^2 = (9*10^9*1.5*10^-6*cos45)/0.28^2 = 121759.45 N/C

E1y = -k*q1*sin45/r^2 = -(9*10^9*1.5*10^-6*sin45)/0.28^2 = -121759.45 N/C

E2x = k*q2*cos45/r^2 = (9*10^9*8.2*10^-6*cos45)/0.28^2 = 665618.37 N/C

E2y = k*q2*sin45/r^2 = (9*10^9*8.2*10^-6*sin45)/0.28^2 = 665618.37 N/C

E3x = k*q3*cos45/r^2 = (9*10^9*3.9*10^-6*cos45)/0.28^2 = 316574.59 N/C

E3y = -k*q3*sin45/r^2 = -(9*10^9*3.9*10^-6*cos45)/0.28^2 = -316574.59 N/C

E4x = k*q4*cos45/r^2 = -(9*10^9*8*10^-6*cos45)/0.28^2 = -649383.78 N/C

E4y = -k*q1*sin45/r^2 = -(9*10^9*8*10^-6*cos45)/0.28^2 = -649383.78 N/C

Ex = 121759.45 + 665618.37 + 316574.59 - 649383.78 = 454568.63 N/C

Ey = -121759.45 + 665618.37 - 316574.59 - 649383.78 =-422099.45 N/C

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.