A cylinder of pure oxygen has a volume of 20 liters and a pressure of 100 atm. (
ID: 1427460 • Letter: A
Question
A cylinder of pure oxygen has a volume of 20 liters and a pressure of 100 atm.
(A) What is the thermal energy of the gas at room temperature?
(B) What is the mean free path in the gas?
(C) The valve is not quite shut and the gas escapes and expands sloooowly/isothermally into the room. What is the change in the gas’s thermal energy? (It will be mixed with the room’s air, of course, but I just care about the thermal energy that the oxygen now has.)
(D) Instead of the slow leak described in (C), the valve breaks off and the gas expands quickly into the room. What is the change in the gas’s thermal energy?
Explanation / Answer
A) Here, Temperature of gas = 20 * 100/0.0821
= 24360.53 K
=> Thermal energy = 3/2 * 1.38 × 10-23 * 24360.53
= 5.0426 * 10-19 J
B) mean free path is the average distance traveled by a moving particle between successive impacts (collisions), which modify its direction or energy or other particle properties.
Mean free path of oxygen is 6 * 10-6 cm
C) For isothermally expansion , thermal energy will remain the same .
=> Thermal energy = 3/2 * 1.38 × 10-23 * 24360.53
= 5.0426 * 10-19 J
=> there is no change in thermal energy
D) In this case, the gas thermal energy will decreases .
=> Thermal energy = 3/2 * 1.38 × 10-23 * 300
= 6.21 * 10-21 J
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