The large figure shows the equipo- tential surfaces for a long corner-shaped con

Question

The large figure shows the equipo-

tential surfaces for a long corner-shaped con-

ductor and a long round conductor, both inside

a square metal pipe, in cross section. The en-

closure is at ground potential (0V), the corner

is at +4000V, and the cylinder is at -4000V. The equipoten-

tial contour lines are 1 kV apart and labelled in kilovolts; the

letters denote points on the lines. A cm scale is shown.

Enter ALL correct statements, e.g., BCD.

A) The electric field E at f is zero.

B) The electric field ~E at j points north.

C) The force on a negative charge at c points west.

D) The force on a positive charge at e points west.

E) The potential energy of a charge at f is zero.

F) The electric field ~E at k points north.

23. [1pt] Calculate the work required to move a charge of

? 3. 10 °¡ 10?13 C from f to e .

24. [1pt] Calculate the magnitude of the electric field at f .

22. [1pt] The large figure shows the equipo- tential surfaces for a long corner-shaped con- ductor and a long round conductor, both inside a square metal pipe, in cross section. The en closure is at ground potential (0 V), the corner is at +4000 V, and the cylinder is at -4000 V. The equipoten- tial contour lines are 1 kV apart and labelled in kilovolts; the letters denote points on the lines. A cm scale is shown. +1 cm 1 A1

Explanation / Answer

22. CDE

A is wrong because at f, potential is zero not field

B is wrong because electric field at j points west as eletric field's direction is perpendicular to equipotential curve and points in the direction in which potential decreases

C is right, field points east, charge is negative, so force points west

D is right,  field points west, charge is positive, so force points west

E is right, because Potential energy U = qV...and V (potential)is zero at f

F is wrong because electric field points South ( in the direction in which potential decreases)

23. W = - q (V2-V1) = 3.10 X 10-13 (3000-0) = 9.3 X 10-10 J

24. E= dV/dx = 2000V/(0.7cm) = 2000/0.007 V/m = 285714 V/m (unit can be either V/m or N/C)

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