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The large figure shows the equipotential surfaces for a long corner-shaped condu

ID: 1429879 • Letter: T

Question

The large figure shows the equipotential surfaces for a long corner-shaped conductor and a long round conductor, both inside a square metal pipe, in cross section. The enclosure is at ground potential (0 V), the corner is at +4000 V, and the cylinder is at -4000 V. The equipotential contour lines are 1 kV apart and labelled in kilovolts; the letters denote points on the lines. A cm scale is shown. Enter ALL correct statements, e. g., BCD. The electric field E at f is zero. The electric field E at j points north. The force on a positive charge at c points west. The force on a positive charge at a points east. The potential energy of a charge at f is zero. The electric field E at h points north. Calculate the work required to move a charge of -3.50 Times 10^-13 C from g- to a. Calculate the magnitude of the electric field at e.

Explanation / Answer

(A) False, the voltage is still changing across ‘f’ even though it is instantaneously zero.

(B) False, a positive test charge will be attracted to the negative charge, thus it will point west.

(C) False, the (+) charge would be repelled away from the positive charge, thus the force would be east.

(D) False, the positive test charge wants to move away from the high positive charge already there, it will move west.

(E) True, as f lies on an equipotential surface where potential due to corner shaped conductor and cylindrical conductor cancel each other out because it is equidistance from both conductors.

(F) False, a positive test charge would be repelled at k, along the electric field pointing downward (south).

(23) W = qV

Now V = Va - Vg = (1000 V) - (-1000 V) = 2000 V

W = (-3.50 x 10-13 C) * (2000 V)

W = - 7 x 10-10 J

(24) E = - V / L

E = - (4000 V - 3000 V) / (1.3 cm - 1.0 cm)

E = - (1000 V) / (0.3 cm)

E = - (1000 V) / (0.003 m)

E = - 333333.33 V/m

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