IP Three resistors. R_1 = 29 Ohm, R_2 = 77 Ohm, and R_3 = R, are connected in pa

Question

IP Three resistors. R_1 = 29 Ohm, R_2 = 77 Ohm, and R_3 = R, are connected in parallel with a 12 V battery. The total current flowing through the battery is 0.88 A. Find the value of resistance R Express your answer using two significant figures. Find the current through each resistor Enter your answers numerically separated by commas. Express your answers using two significant figures. If the total current in the battery had been greater than 0.88 A. would your answer to A have been larger or smaller?

Explanation / Answer

part a )

I = V/Req =

Req = V/I = 12/0.88 = 13.6364 ohm

in parallel equivalent resistance

1/Req = 1/R1 + 1/R2 + 1/R3

1/13.6364 = 1/29 + 1/77 + 1/R

R = 38.66 = 39 ohm

part b )

since all resistor in parallel so voltage drop remain same for all resistor

I = V/R

I1 = 12/29 = 0.41

I2 = 12/77 = 0.16

I3 = 12/38.66 = 0.31

part c )

if current increase , then R will be smaller

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