IP Three resistors R_1 = 30 ohm, R_2 = 67ohm, and R_3 = R, are connected in para

Question

IP Three resistors R_1 = 30 ohm, R_2 = 67ohm, and R_3 = R, are connected in parallel with a 12 V battery The total current flowing through the battery is 0.88 A. Find the value of resistance R. Express your answer using two significant figures. R = ohm Find the current through each resistor. Enter your answers numerically separated by commas. Express your answers using two significant figures. I_1, I_2, I_3 = A If the total current in the battery had been greater than 0.88 A, would your answer to part A have been larger or smaller? larger smaller

Explanation / Answer

herec we observed the resistance R1 ,R2 and R are parallel connection

the equivalent resistance Req=30*67*R/30*67+67R+30R

now we find the resistance R3

V=I*Req

12=0..88*2010R/2010+30R+67R

24120+1164R=1768.8R

604.8R=24120

resistance R3=R=39.9 ohm

now we find the current on each resistance

current on resistance R1=>I1=30*0.88/30+67+39.8=0.193 A

current on resistance R2=>I2=67*0.88/30+67+39.9=0.431 A

current on resistance R3=>I3=39.9*0.88/30+67+39.9=0.26 A

the current on the battery is larger

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