Two children fight over a 200 g stuffed bear. The 25 kg boy pulls to right with
ID: 1431267 • Letter: T
Question
Two children fight over a 200 g stuffed bear. The 25 kg boy pulls to right with a 15 N force and the 20 kg girl pulls to the left with a 17 N force. Ignore all other force on the bear. (Suck as weight).Part c What is the magnitude of the acceleration?
Part d Two children fight over a 200 g stuffed bear. The 25 kg boy pulls to right with a 15 N force and the 20 kg girl pulls to the left with a 17 N force. Ignore all other force on the bear. (Suck as weight).
Part c What is the magnitude of the acceleration?
Part d
Part c What is the magnitude of the acceleration?
Part d
Explanation / Answer
It is given that,net force on the bear is
F = 17 - 15 = 2 N
Hense,acceleration of bear is: a = F / m = 2 / [200*10^(-3)] = 10 m/sec^2
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