A straight vertical wire carries a current of 1.35 A downward in a region betwee

Question

A straight vertical wire carries a current of 1.35 A downward in a region between the poles of a large electromagnet where the field strength is 0.590 T and is horizontal.

Part E What are the direction of the magnetic force on a 1.00 cm section of this wire if the magnetic-field direction is 20.0 o south of west ? Please, enter your answer as an angle's value north of west.

Part F What are the magnitude of the magnetic force on a 1.00 cm section of this wire if the magnetic-field direction is 20.0 o south of west ?

Explanation / Answer

Current = I = 1.35 A ( downward )

Magnetic field = B =0.590 T ( horizontal)

Wire length = L = 1.00 cm =0.01 m

Angle between wire length and magnetic field = thetqa = 90 degree

Magnitude of the magnetic force = F = BIL sin theta

F =0.590*1.35*0.01*sin 90

Magnitude of the magnetic force=F = 7.96*10^-3 N

The direction of force is horizontal,20 degree west of north.

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