Three Identical Masses Three identical very dense masses of 4000 kg each are pla

Question

Three Identical Masses Three identical very dense masses of 4000 kg each are placed on the x axis. One mass is at x_1 = -140 cm, one is at the origin, and one is at x_2 = 400 cm. What is the magnitude of the net gravitational force F_gray on the mass at the origin due to the other two masses? Take the gravitational constant to be G = 6.67 Times 10^-11 N. m^2/kg^2. Express your answer in newtons to three significant figures. What is the direction of the net gravitational force on the mass at the origin due to the other two masses? +x direction -x direction

Explanation / Answer

F= Gm1m2 /d12+Gm3m2 /d22

F=6.67*10-11* 4000*4000/(1.4*1.4) + 6.67*10-11* 4000*4000/(4*4)

= 0.0005445 - 0.0000667 = 0.000478N

partb

The direction is -x direction, because we can see in part a that magnitude of force (attraction) by first body is larger

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