Three Infinite Straight Wires 1 2 3 4 5 1 7 Three infinite straight wires are fi
ID: 1791502 • Letter: T
Question
Three Infinite Straight Wires
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Three infinite straight wires are fixed in place and aligned parallel to the z-axis as shown. The wire at (x,y) = (-12 cm, 0) carries current I1 = 2.7 A in the negative z-direction. The wire at (x,y) = (12 cm, 0) carries current I2 = 0.7 A in the positive z-direction. The wire at (x,y) = (0, 20.8 cm) carries current I3 = 7.4 A in the positive z-direction.
1)
What is Bx(0,0), the x-component of the magnetic field produced by these three wires at the origin?
T
Your submissions:
7.115*10^-6
Computed value:
7.115E-06
Submitted:
Monday, October 30 at 4:05 PM
Feedback:
Your answer has been judged correct; the exact answer is: 7.11538461538462 × 10-6.
2)
What is By(0,0), the y-component of the magnetic field produced by these three wires at the origin?
T
Your submissions:
-5.66*10^-6
Computed value:
-5.66E-06
Submitted:
Monday, October 30 at 4:06 PM
Feedback:
Your answer has been judged correct; the exact answer is: -5.66666666666667 × 10-6.
3)
What is Fx(1), the x-component of the force exerted on a one meter length of the wire carrying current I1?
N
4)
What is Fy(1), the y-component of the force exerted on a one meter length of the wire carrying current I1?
N
5)
What is Fx(2), the x-component of the force exerted on a one meter length of the wire carrying current I2?
N
d IExplanation / Answer
3)
F1x = F21x + F31x
F21x = -uo*I1*I2*L/(2*pi*d)
F21x = -4*pi*10^-7*2.7*0.7*1/(2*pi*0.24)
F21x = -1.575*10^-6 N
F31x = -uo*I1*I3*cos60*L/(2*pi*d)
F31x = -4*pi*10^-7*2.7*7.4*cos60*1/(2*pi*0.24)
F31x = -8.325*10^-6
F1x = -9.9*10^-6 N <<<<------------ANSWER
========================================================================
4)
Fy(1) = F21y + F31y
F21y = 0
F31y = -uo*I1*I3*sin60*L/(2*pi*d)
F31y = -4*pi*10^-7*2.7*7.4*sin60*1/(2*pi*0.24)
F31y = -1.44*10^-5 N
Fy(1) = -1.44*10^-5 N <<<<------------ANSWER
==========================================
Fx(2) = F12x + F32x
F12x = uo*I1*I2*L/(2*pi*d)
F12x = 4*pi*10^-7*2.7*0.7*1/(2*pi*0.24)
F12x = 1.575*10^-6 N
F31x = uo*I1*I3*cos60*L/(2*pi*d)
F31x = 4*pi*10^-7*2.7*7.4*cos60*1/(2*pi*0.24)
F31x = 8.325*10^-6
Fx(2) = 9.9*10^-6 N <<<<------------ANSWER
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