A series RLC circuit is shown in the figure. The circuit is powered by an AC sou

Question

A series RLC circuit is shown in the figure. The circuit is powered by an AC source. The peak emf of the AC source is 40 volt. The resistance is R = 180 oh; the capacitance is C = 33 mu F; the inductance is L = 49 mH. What is the resonant frequency of this RLC circuit (in the unit of Hertz (Hz))? Hz F = w/2 pie What is the peak current in the circuit at resonance? At resonant frequency, how much is the reactance of the capacitor? oh At resonant frequency, how much is the reactance of the inductor? oh

Explanation / Answer

Resonance frequency = 1/(2LC) = 125 Hz
For a series RLC circuit at certain frequency called resonant frequency, the following points must be remembered. So at resonance:

  
Inductive reactance XL is equal to capacitive reactance XC.
XL = 2fL = 38.5
XC = 1/(2fC) = 38.5

  
Total impedance of circuit becomes minimum which is equal to R i.e Z = R.

  
Circuit current becomes maximum as impedance reduces, I = V / R = 40/180 = 0.22 A

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