two loudspeakers,separated by a distance of D1=2.50m, are in phase. assume the a

Question

two loudspeakers,separated by a distance of D1=2.50m, are in phase. assume the amplitudes of the sound from speakers are approximately the same at the position of a listener, who is D2=4.33m directly in from of one of the speakers . consider the audible range for a normal hearing is 20 hz to 20 khz.
a) what is the lowest frequency that gives the minimum signal( destructive interference)
b) what is the lowest frequency that gives the maximum signal ( constructive interference
"remember speed of sound 343"

Explanation / Answer

the difference in distance to the listener is sqrt(4.33^2 + 2.50^2) - 4.33 = 0.66m

A) minimum destructive interference occurs when d = /2 so = 2*d = 2*0.66 = 1.32m

so f = c/ = 343/1.32 = 260Hz

the next frequency is d = 3/2 so = 2*d/3 = 2*0.66/3 = 0.44m

so f = c/ = 343/ 0.44 = 780Hz

d) constructive interference occurs at d = = 0.66m

f = c/ = 343/0.66 = 519Hz

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