An ideal solenoid has 5220 turns per metre and radius 2.6 cm, length 40 cm. The

Question

An ideal solenoid has 5220 turns per metre and radius 2.6 cm, length 40 cm. The magnetic field inside has magnitude 0.24 T. a. What is the current in the solenoid? b. A second ideal solenoid is placed inside the first solenoid such that their radial axes line up. The radius of this solenoid is 1.0 cm, and it also has 5220 turns per metre and is 40 cm long. What current must be passing through the second solenoid if the magnetic field inside the second solenoid is measured to be 0 T

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Explanation / Answer

a) As B = u0*I*n======> I = B/u0*n [where n = N/L = No. of turns per unit length = 5220*0.40 = 2088]

I = (0.24)/(4pi*10^-7*2088) = 91.5 A

b) The field inside both solenoids is B = u0*I*(n1 - n2) = 0 [n1 = n2 = 2088]

From above equation, B the magnetic field inside the second solenoid will always remains 0 T, whether currnet could be any value.

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