While leaning out a window that is 6.4 m above the ground, you drop a 0.60-kg ba

Question

While leaning out a window that is 6.4 m above the ground, you drop a 0.60-kg basketball to a friend at ground level. Your friend catches the ball at a height of 1.4 m above the ground. Determine the following.

(a) the amount of work done by the force of gravity on the ball

(b) the gravitational potential energy of the ball-earth system, relative to the ground when it is released

(c) the gravitational potential energy of the ball-earth system, relative to the ground when it is caught

(d) the ratio of the change (PEf PE0) in the gravitational potential energy of the ball-earth system to the work done on the ball by the force of gravity

Explanation / Answer

Net fall in height of ball= 6.3-1.4= 5 m

a)  work done by the force of gravity on the ball = Mg*h = 0.6*9.8*5 = 29.4 J (ans)

b) gravitational potential energy of the ball-earth system, relative to the ground when it is released = 0.6*9.8*6.4 = 37.63 J (ans)

c) the gravitational potential energy of the ball-earth system, relative to the ground when it is caught = 0.6*9.8*1.4 = 8.23 J

d) ratio of the change (PEf PE0) in the gravitational potential energy of the ball-earth system to the work done on the ball by the force of gravity = (8.23 -37.63)/(29.4) =-1 (ans)

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