While leaning out a window that is 6.5 m above the ground, you drop a 0.60 kg ba

Question

While leaning out a window that is 6.5 m above the ground, you drop a 0.60 kg basketball to a friend at ground level. Your friend catches the ball at a height of 1.1 m above the ground. Determine the following. the amount of work done by the force of gravity on the ball the gravitational potential energy of the ball earth system, relative to the ground when it is released the gravitational potential energy of the ball earth system, relative to the ground when it is caught the ratio of the change (PE_1 - PE_0) In the gravitational potential energy of the ball earth system to the work done on the ball by the force of gravity

Explanation / Answer

Given ball is dropped from a height of 6.5 m, of mass m= 0.6 kg, to a level when your friend cactched is 1.1 m

a) work done by force of gravity on ball = mgh = 0.6*9.8*6.5 = 38.22 J
b) gravitational potential energyof the ball- earth system, relative to the ground when it is released is Wg = mg*h = 0.6*9.8*6.5 = 38.2 J

c) gravitational potential energyof the ball- earth system, relative to the ground when it is caught is Wg = mg*h = 0.6*9.8*1.1 = 6.5 J

d) P.E f - P.E i = 0.6*9.8*1.1 - 0.6*9.8*6.5 = -31.75 J

  
   work done by force of gravity on ball= 38.22 J

now rati0 is 31.75/38.22 = 0.830

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