While leaning out a window that is 6.6 m above the ground, you drop a 0.60-kg ba
ID: 1445176 • Letter: W
Question
While leaning out a window that is 6.6 m above the ground, you drop a 0.60-kg basketball to a friend at ground level. Your friend catches the ball at a height of 1.7 m above the ground. Determine the following.
(a) the amount of work done by the force of gravity on the ball ___J
(b) the gravitational potential energy of the ball-earth system, relative to the ground when it is released _____J
(c) the gravitational potential energy of the ball-earth system, relative to the ground when it is caught ____J
(d) the ratio of the change (PEf PE0) in the gravitational potential energy of the ball-earth system to the work done on the ball by the force of gravity
PE / W=Explanation / Answer
(a)
workdone by force of gravity is W = mg(h1 - h2) = (0.6)(9.8)(6.6-1.7) = 28.8 J
(b)
the gravitational potential energy of the ball-earth system, relative to the ground when it is releasedis,
PE1= mgh1 = (0.6)(9.8)(6.6) = 38.8 J
the gravitational potential energy of the ball-earth system, relative to the ground when it is catched is,
PE2= mgh2 = (0.6)(9.8)(1.7) = 10.0 J
the ratio of the change (PEf PE0) in the gravitational potential energy of the ball-earth system to the work done on the ball by the force of gravity is
PE2 -PE1 / W = 1.0
(c) the gravitational potential energy of the ball-earth system, relative to the ground when it is catched is, PE2= mgh2 = (0.6)(9.8)(1.7) = 10.0 J
(d)the ratio of the change (PEf PE0) in the gravitational potential energy of the ball-earth system to the work done on the ball by the force of gravity is PE2 -PE1 / W = 1.0
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