While hauling a log in the back of a flatbed truck, you are pulled over by the s
ID: 1959354 • Letter: W
Question
While hauling a log in the back of a flatbed truck, you are pulled over by the state police. Although the log can't roll sideways. The police claim that the log could have slid out the back of the truck when accelerating from rest You claim that the truck couldn't possibly accelerate at the level needed to achieve such an effect Regardless. the police write a ticket anyway and now your day in court is approaching The log has a mass of m middot 984 kg. the truck has a mass of M * 9. 40 * 101 kg. According to the truck manufacturer, the truck can accelerator from 0 to 55 mph in 250 seconds, but this does not account for the additional mass of the log Calculate the minimum coefficient of static friction needed to keep the log in the back of the truck.Explanation / Answer
Here is what I solved before, please modify the figures as per your question. Please let me know if you have further questions. Ifthis helps then kindly rate 5-stars.
While hauling a log in the back of a flatbed truck, you are pulled over by the state police. Although the log can't roll sideways, the police claim that the log could have slid out the back of the truck when accelerating from rest. You claim that the truck couldn't possibly accelerate at the level needed to achieve such an effect. Regardless, the police write a ticket anyway and now your day in court is approaching.The log has a mass of m = 954 kg; the truck has a mass of M = 8850 kg. According to the truck manufacturer, the truck can accelerate from 0 to 55 mph in 23.0 seconds, but this does not account for the additional mass of the log. Calculate the minimum coefficient of static friction ?s needed to keep the log in the back of the truck.
Answer
the speed achieved by the truck in 23 seconds with the log=8850*55/(8850+954)=49.65 miles/hr=22.2 m/s
Average acceleration=22.2/23=0.965 m/s2
let ? be the minimum coefficient of static friction.
For the log to stay on the truck, ?mg=ma
?=a/g=0.0985
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