A 10 kg box is held against a spring (k-2000 N/m) compressed 2 meters from it\'s

Question

A 10 kg box is held against a spring (k-2000 N/m) compressed 2 meters from it's equilibrium position. The box is then released. All surfaces are frictionless, except for a 10 meter patch between points A and B with a coefficient of kinetic friction of 0.5 (mu_k = 0.5) between the box and the patch. The box then enters a circular depression with a radius of 25 meters. Answer the following questions based on this situation: The speed of the box at point A, just before entering the patch and after the box has lost contact with the spring The work done by frictional path between points A and B The speed of the block at point C The normal force of the surface on the block at point C

Explanation / Answer

Applying moment equilibrium at A

=> 40 * 9.8 * 4   + 35 * 9.8 * 2 = Fb * 1

=>   Fb =   2254 N             (upwards)

Applying moment equilibrium at B

=>   40 * 9.8 * 3 + 35 * 9.8 * 1 = - Fa * 1

=> Fa = - 1519 N          (downwards)

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.