A 10 kg bowling ball is suspended inside an elevator by a rope. (a) Find the ten

Question

A 10 kg bowling ball is suspended inside an elevator by a rope. (a) Find the tension in the rope as the elevator starts to accelerate upward from rest at 1.5 m/s2. (b) After reaching a speed of 10 m/s the elevator continues to the 90th floor at a constant speed. Find the tension in the rope as it travels at constant speed. (c) As it reaches the top floor, it decelerates at 2.5 m/s2 until it stops at the 94th floor. Find the tension in the rope as the elevator decelerates. (d) How far does the ball travel while accelerating and decelerating?

Explanation / Answer

A) T = m(g+a) = 10*(9.8+1.5) = 113 N answer

B) again T = m(g+a) = 10*(9.8+0) = 98 N answer

C) Again T = 10*(9.8-2.5) = 73 N answer

D) while accelerating s= v^2 /2a = 10^2 /(2*1.5) =33.3 m

While decelerating s = u^2/2a = 10^2 /(2*2.5) = 20 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.