A 10 kg blockis set in motion up a 20 degree inclined plane with an initialspeed
ID: 1763887 • Letter: A
Question
A 10 kg blockis set in motion up a 20 degree inclined plane with an initialspeed of 8.0 m/s. With no additional forces applied, theblock comes to rest after traveling some distance up the plane.
a. ACalculate the change inkinetic energy of the block.
b. B. Calculate the change in gravitational potential energy of theblock.
c. C.Assuming the interfacebetween the block and the plane is frictionless, calculate thedistance up the surface of the plane the block will travel.
d. D. Ifthe coefficient of kinetic friction between the block and the planeis 0.10, calculate the distance up the surface of the plane theblock will travel.
Please show All work and Formulasused to get the answer thank you!
Explanation / Answer
mass m = 10 kgAngle = 20 degree initial speed u = 8.0 m/s (A). the change in kinetic energy of the block = ( 1/ 2)m u ^ 2 = 320 J (B). the change in gravitational potential energy of theblock = 320 J c. ( C ) .plane is frictionless.So, accleration a = - g sin = - 3.351 m / s ^ 2 final velocity v = 0 from the relation v ^ 2 - u ^ 2 = 2aS distance S = [ v ^ 2 - u ^ 2] / 2a = 9.547 m
d. (D.) coefficient of kinetic friction between the block andthe plane = 0.10 Accleration a ' = - [ g sin - g cos] =-2.43 m / s ^ 2
the distance up the surface of the plane the block willtravel S ' = [ v ^ 2- u ^ 2 ] / 2a' = 13.168 m
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