You drop a 2.30 kg book to a friend who stands on the ground at distance D = 13.
ID: 1443414 • Letter: Y
Question
You drop a 2.30 kg book to a friend who stands on the ground at distance D = 13.0 m below. If your friend's outstretched hands are at distance d = 1.70 m above the ground (see the figure), (a) how much work Wg does the gravitational force do on the book as it drops to her hands? (b) What is the change U in the gravitational potential energy of the book-Earth system during the drop? If the gravitational potential energy U of that system is taken to be zero at ground level, what is U (c) when the book is released and (d) when it reaches her hands? Now take U to be 100 J at ground level and again find (e) Wg, (f ) U, (g) U at the release point, and (h) U at her hands.
Explanation / Answer
As given in the question,
m = 2.3 kg, D = 13 m and d = 1.7 m
(a) Work done by the gravitational force do on the book as it drops to her hands,
Wg = m*g*(D - d) = (2.3)*(9.8)*(13 - 1.7) = 254.7 J
(b) The change U in the gravitational potential energy of the book-Earth system during the drop,
U = Wg = 254.7 J
If the gravitational potential energy U of that system is taken to be zero at ground level:
(c) The gravitational potential energy of system when the book is released,
U = m*g*D = (2.3)*(9.8)*(13) = 293.02 J
(d) The gravitational potential energy of system when it reaches her hands,
U = m*g*d = (2.3)*(9.8)*(1.7) = 38.32 J
Now take U to be 100 J at ground level and again repeating the above problems:
(e) Work done by the gravitational force do on the book as it drops to her hands,
Wg = m*g*(D - d) = (2.3)*(9.8)*(13 - 1.7) = 254.7 J
(f) The change U in the gravitational potential energy of the book-Earth system during the drop,
U = Wg = 254.7 J
(g) The gravitational potential energy of system when the book is released,
U = 100 + m*g*D = 100 + (2.3)*(9.8)*(13) = 393.02 J
(h) The gravitational potential energy of system when it reaches her hands,
U = 100 + m*g*d = 100 + (2.3)*(9.8)*(1.7) = 138.32 J
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