A mass m 1 = 5.7 kg rests on a frictionless table and connected by a massless st

Question

A mass m1 = 5.7 kg rests on a frictionless table and connected by a massless string to another mass m2 = 5.3 kg. A force of magnitude F = 33 N pulls m1 to the left a distance d = 0.81 m.

1)How much work is done by the force F on the two block system?

___________J

2)How much work is done by the normal force on m1 and m2?

______________J

3)What is the final speed of the two blocks?

_______________m/s

4)How much work is done by the tension (in-between the blocks) on block m2?

_____________J

5)What is the tension in the string?

_______________N

7)What is the NET work done on m1?

___________________J

Explanation / Answer

1 . w = F.d = 33*0.81 = 26.73 J

2 ) 0 because it is perpendicular to velocity or motion

3) find the tension first

F= m1*a

F -T = m1a

T = m2*a

from 1 & 2 we got

a = F/ ( m1+m2) = 33/ ( 5.7+5.3) = 3 m/s^2

T= m2*a = 5.3*3 = 15.9

wotk by tension = 15.9*0.81 = 12.87 J

5 ) T= 15.9 N

6) net work = (F-T)*d = (33-15.9) *0.81 = 13.85 J

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