A small lightbulb is 1.02 m from a screen. Part A If you have a convex lens with

Question

A small lightbulb is 1.02 m from a screen.

Part A If you have a convex lens with 17 cm focal length, where are the two lens locations that will project an image of the lightbulb onto the screen? Express your answers using two significant figures separated by a comma. between the lightbulb and the screen at d1, d2 =

Part B What’s the magnification in the first case (smaller distance from the lightbulb)? Express your answer using two significant figures. M =

Part C What’s the magnification in the second case (larger distance from the lightbulb)? Express your answer using two significant figures. M =

Explanation / Answer

A)

f = 17 cm

let u and v are object and image distances.

u + v = 1.02 m

u + v = 102 cm

v = 102 - u

Apply,

1/u + 1/v = 1/f

1/u + 1/(102-u) = 1/17

17*((102-u) + u) = (102-u)*u

1734 = 102*u - u^2

u^2 - 102*u + 1734 = 0

on solving the above equation we get

u = 21.6 cm

u = 80.4 cm

B) M = -v/u = -(102-21.6)/21.6 = -3.7

C) M = -v/u = -(102 - 80.4)/80.4 = 0.27

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